Problem 7.5:
The value of R is between 100 and 1,000 ohms.
Problem 7.8: This should let you check your answer:
vo(0+) = -15 V,
time constant = 0.01 sec.
Problem 7.15:
(a)
iL(t) = 6 e-500t A,
t >= 0. (Show all of your work!!)
Problem 7.19: (a) vo(t) = -7.5
e-50,000t (V), t >= 0+.
(b) Here is a hint. For large t,
io = -3.125 mA.
Problem 7.21: See back of book, but here are some answers.
(a)
v1(t) = 60 e-125t
+ 15 (volts), for t >= 0.
(c) Power dissipated in resistor = 4,500 micro J.
Problem 7.27:io(t) = -625 e-1000t
micro A, t >= 0+.
Problem 7.30: (a) Current in screwdriver at t = 0+ is 1.65 A.
Current in screwdriver at large t is 25 mA.
(b) The answers in (a) should be enough for you to verify the
answer you obtain for (b).
Problem 7.32:
The range of each answer is as follows (you should find
the exact answers).
(a) Percentage of initial energy dissipated in 25 k ohm resistor:
5% to 10%.
(b) Percentage of initial energy dissipated in 625 ohm resistor:
0% to 5%.
Percentage of initial energy dissipated in 15 k ohm resistor:
10% to 15%.
(c) Percentage of initial energy trapped: 75% to 80%.